Create Your Own Random Password Generator Using Python [Free Source Code]

This program generates random password using simple python script. This script can be a good small python project to be shown in your class or to your colleagues.

 

To begin programming our random password generator, first, we need to import 'random module' from python 3. This is built in module and you don't need to install any package for that. Simply write

 

import random

 

Next we define list to store password, which will be generated by script.

 

password = []

 

Next step is to define lists of characters, numbers and symbols for password. Keep in mind that these are user generated lists you can customize them according to your preference.

 

letters = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','a','b','c', 'd', 'e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

 

numbers = ['1','2','3','4','5','6','7','8','9','0']

 

characters = ['+','(',')','*','%','^','$','_','@','=']

 

 

Now that we have laid basic bricks for our code, we must know the length of password that user want’s to generate and number of characters or symbols or numbers user wants to add to its password. To do this we define three input statements which ask user for its preference regarding password.  Simply write

no_letters = int(input("How many letters would you like in your password?\n"))

no_numbers = int(input("How many number would you like?\n"))

no_characters = int(input("How many symbols would you like?\n"))

 

above three statements take input from user and store them in variables called no_letters, no_numbers and no_characters, [You can use your own naming scheme], and store them as int type.

Next we start generating password by simply looping through our lists [letters, numbers and characters]. Go ahead and write

for x in range(0,no_letters):

    password += random.choice(letters)

 

for x in range(0,no_numbers):

    password += random.choice(numbers)

 

for x in range(0,no_characters):

    password += random.choice(characters)

 

now that password has been generated but it will contain sequential characters, just for understanding the password is not random so we will shuffle it by writing

 

random.shuffle(password)

 

and then we store it in a new password like this.

 

random.shuffle(password)

 

new_password = ""

 

for char in password:

    new_password += char

 

and in the last we just simply print it by writing

 

print(f"Your password is {new_password}")

 

putting everything together. Below is the complete code of random password generator python project. This code should run just fine on your machine.

 

 

Source Code 👇

#-------------------------------------------------------------------

#This program generates password randomly

import random

password = []

letters = ['A','B','C','D','E','F','G','H','I','J','K','L',

'M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','a',

'b','c', 'd', 'e','f','g','h','i','j','k','l','m','n','o','p',

'q','r','s','t','u','v','w','x','y','z']

numbers = ['1','2','3','4','5','6','7','8','9','0']

characters = ['+','(',')','*','%','^','$','_','@','=']

no_letters = int(input("How many letters would you like in your password?\n"))

no_numbers = int(input("How many number would you like?\n"))

no_characters = int(input("How many symbols would you like?\n"))

for x in range(0,no_letters):

    password += random.choice(letters)

for x in range(0,no_numbers):

    password += random.choice(numbers)

for x in range(0,no_characters):

    password += random.choice(characters)

random.shuffle(password)

new_password = ""

for char in password:

    new_password += char

print(f"Your password is {new_password}")

#-------------------------------------------------------------------

Output 👇

How many letters would you like in your password?

12

How many number would you like?

4

How many symbols would you like?

2

Your password is Tw5@4o1*b3ewiYQSzw

If you faced any kind of difficulty in writing this code or executing it, feel free to write in comment section below.

Create Your Own Random Password Generator Using Python [Free Source Code]

[Solved] Program To Check Leap Year In Python Using Functions

[Solved] Program To Check Leap Year In Python Using Functions

In this tutorial, we will learn how to calculate leap year with a simple python script. First, we need to understand the rules behind a year being a leap year to write the code. The steps to calculate leap year are following

1. If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.

2. If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.

3. If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.

4. The year is a leap year (it has 366 days).

5. The year is not a leap year (it has 365 days).

For more information and detailed examples, we can read This article. 

To write a python script, we will create a flowchart of the rules as mentioned earlier.

After creating a flowchart, we can start writing python code.

Step 1: Ask User for Input

To allow users to input a value, we need to add an 'input' statement in our program. The 'input' statement displays a string and returns the text input by users, so we need to store it in a variable. We will define a variable named 'user_input', so our first statement becomes this.

user_input = input(“"Enter a Year: ")

However, the input statement returns any value input by the user as text. To handle this, we add the 'int' statement before the 'input' statement.

user_input = int(input(“"Enter a Year: "))

Step 2: Process the Input

Once the user has input, we have our value stored in a variable name 'user_input' we can process it as 'user_input'. First, we divide the 'user_input' by 4. Please keep in mind that we will use the modulus division method because we want to check if the remainder is 0 or not.

 If the remainder is 0, then we divide it by 100. However, before we check the remainder of the division of 100, if we re-read Rule 2 mentioned above, we can see if we do not check the remainder of the division of 100 for 0. However, for 1, we can skip step 3 and directly go to step 4. So our code becomes

if (year%4==0):

        if(year%100==1):

            print(f"{year} is a leap year!!") 

**notice the indentation? Keep it that way because python uses indentation to nest statements.

We have used two 'if' statements to check the leap year, but when both the 'if' statements are false, we will divide 'user_input' by 400 and check the remainder for 0. We add 'else statement for this purpose.

def leap_check(year):

    if (year%4==0):

        if(year%100==1):

            print(f"{year} is a leap year!!")    

        else:

            if(year%400==0):

                print(f"{year} is a leap year!!")

Then we declare everything else as not a leap year.

if (year%4==0):

        if(year%100==1):

            print(f"{year} is a leap year!!")    

        else:

            if(year%400==0):

                print(f"{year} is a leap year!!")

            else:

                print(f"{year} is not a leap year!!")

    else:

        print(f"{year} is not a leap year!!")

Now wrap up all the code in a function and call it in main.

def leap_check(year):

    if (year%4==0):

        if(year%100==1):

            print(f"{year} is a leap year!!")    

        else:

            if(year%400==0):

                print(f"{year} is a leap year!!")

            else:

                print(f"{year} is not a leap year!!")

    else:

        print(f"{year} is not a leap year!!")

Step 3: Display outputs

The 'print' function will display the and data already used in the 'if' statement.

user_year = int(input("Enter a Year: "))

leap_check(user_year)

If you find any difficulties in this code or tutorial, please click here or visit Ask For Help.

#Source Code 👇

#-------------------------------------------------------------------------------------

#Leap Year Check 

def leap_check(year):

    if (year%4==0):

        if(year%100==1):

            print(f"{year} is a leap year!!")    

        else:

            if(year%400==0):

                print(f"{year} is a leap year!!")

            else:

                print(f"{year} is not a leap year!!")

    else:

        print(f"{year} is not a leap year!!")

print("\t\t\n\nWelcome!! This programme checks if input year is leap year\n\n")

user_year = int(input("Enter a Year: "))

leap_check(user_year)

#-----------------------------------------------------------------------

OUTPUT 👇

Welcome!! This programme checks if input year is leap year Enter a Year: 2000 2000 is a leap year!!

Dont forget to share your feedback in comments section

Create Your Own Random Password Generator Using Python [Free Source Code]

[Solved] Program To Check Leap Year In Python Using Functions