This 8086 microprocessor assembly program subtracts two decimal digits and prints the output accordingly. If you want to know how can you print a single character in 8086 assembly language you can find it IN THIS LINK. If you have questions or any problems feel free to ask in the comments section.
TITLE THE_LAME_PROGRAMMER
.MODEL SMALL
.STACK 100H
.DATA
DIGIT1 DB 0AH, 0DH, "ENTER FIRST DIGIT: $"
DIGIT2 DB 0AH, 0DH, "ENTER SECOND DIGIT: $"
RESULT DB 0AH, 0DH, "RESULT IS: $"
.CODE
MAIN:
MOV AX, @DATA
MOV DS, AX
MOV DX, OFFSET DIGIT1
MOV AH, 09H
INT 21H
MOV AH, 01H
INT 21H
SUB AL, 30H
MOV BH, AL
MOV DX, OFFSET DIGIT2
MOV AH, 09H
INT 21H
MOV AH, 01H
INT 21H
SUB AL, 30H
MOV BL, AL
CMP BH, BL
JL MINUS
SUB BH, BL
MOV DX, OFFSET RESULT
MOV AH, 09H
INT 21H
MOV DL, BH
ADD DL, 30H
MOV AH, 02H
INT 21H
JMP EXIT
MINUS:
SUB BL, BH
MOV DX, OFFSET RESULT
MOV AH, 09H
INT 21H
MOV DL, '-'
MOV AH, 02H
INT 21H
MOV DL, BL
ADD DL, 30H
MOV AH, 02H
INT 21H
EXIT:
MOV AH, 04CH
INT 21H
END MAIN
